有限数学示例

$[\begin{array}{c} 1 & - 2 & 1 \\ 3 & 2 & - 3 \end{array}]$

解题步骤 1

Perform the row operation $R_{2} = R_{2} - 3 R_{1}$ to make the entry at $2, 1$ a $0$ .

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解题步骤 1.1

Perform the row operation $R_{2} = R_{2} - 3 R_{1}$ to make the entry at $2, 1$ a $0$ .

$[\begin{array}{c} 1 & - 2 & 1 \\ 3 - 3 \cdot 1 & 2 - 3 \cdot - 2 & - 3 - 3 \cdot 1 \end{array}]$

解题步骤 1.2

化简 $R_{2}$ 。

$[\begin{array}{c} 1 & - 2 & 1 \\ 0 & 8 & - 6 \end{array}]$

解题步骤 2

Multiply each element of $R_{2}$ by $\frac{1}{8}$ to make the entry at $2, 2$ a $1$ .

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解题步骤 2.1

Multiply each element of $R_{2}$ by $\frac{1}{8}$ to make the entry at $2, 2$ a $1$ .

$[\begin{array}{c} 1 & - 2 & 1 \\ \frac{0}{8} & \frac{8}{8} & \frac{- 6}{8} \end{array}]$

解题步骤 2.2

化简 $R_{2}$ 。

$[\begin{array}{c} 1 & - 2 & 1 \\ 0 & 1 & - \frac{3}{4} \end{array}]$

解题步骤 3

Perform the row operation $R_{1} = R_{1} + 2 R_{2}$ to make the entry at $1, 2$ a $0$ .

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解题步骤 3.1

Perform the row operation $R_{1} = R_{1} + 2 R_{2}$ to make the entry at $1, 2$ a $0$ .

$[\begin{array}{c} 1 + 2 \cdot 0 & - 2 + 2 \cdot 1 & 1 + 2 (- \frac{3}{4}) \\ 0 & 1 & - \frac{3}{4} \end{array}]$

解题步骤 3.2

化简 $R_{1}$ 。

$[\begin{array}{c} 1 & 0 & - \frac{1}{2} \\ 0 & 1 & - \frac{3}{4} \end{array}]$

有限数学 示例